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-2r^2+72=0
a = -2; b = 0; c = +72;
Δ = b2-4ac
Δ = 02-4·(-2)·72
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-2}=\frac{-24}{-4} =+6 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-2}=\frac{24}{-4} =-6 $
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